midStrings
String Compression (e.g., aabcccccaaa -> a2b1c5a3).
Updated Apr 28, 2026
Short answer
Iterate and count consecutive identical characters, appending count to result.
Deep explanation
Intermediate string problems test your ability to use frequency maps and sliding windows. Iterate and count consecutive identical characters, appending count to result.
Real-world example
Search filters that ignore character order.
Common mistakes
- Inefficiently sorting strings for an anagram check when a frequency map is O(n).
Follow-up questions
- What is the time complexity of sorting?